Question

find the diagonals of a rectangle whose length is 24 cm and area is 432 sq.cm​

Answer 1

Answer:

$l \times b = 432 c {m}^{2} \\ b = 432c {m}^{2} \div 24cm \\ b \: = 18cm \\ \\ digonals \: find \: by \: pythagoras \: theorem \\ \\ therefore \: \: \\ {h}^{2} = {b}^{2} + {p}^{2} \\ = (18cm {)}^{2} + (24cm {)}^{2} \\under root 900c {m}^{2} = 30cm \:$ diagonal = 30 cm

therefore the diagonals of rectangle are 30 cm