Math, asked by asiyajahangir876, 2 months ago

Find the diameter and area of circle whose circumference is 198​

Answers

Answered by sid24malik
0

Step-by-step explanation:

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Answered by DüllStâr
57

 \blue{ \rm Diameter:}

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 \pink{ \rm Given:}

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  • Circumference of circle = 198

 \green{ \rm To \: find: }

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  • diameter of circle

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  • Area of Circle

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 \orange{ \rm Solution: }

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To find diameter first we should know value of radius of circle

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So first let's find radius of Circle.

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we know:

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 \bigstar \boxed{ \rm{}Circumference \: of \: circle = 2 {\pi}r}

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By using this formula we can find value of r(radius)

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 \dashrightarrow \: \sf{}Circumference \: of \: circle = 2 {\pi}r

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 \dashrightarrow \: \sf{}198= 2 {\pi}r

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 \dashrightarrow \: \sf{}198= 2 \times  \dfrac{22}{7} \times r

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 \dashrightarrow \: \sf{}2 \times  \dfrac{22}{7} \times r = 198

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 \dashrightarrow \: \sf{}r = 198 \times  \dfrac{1}{2}  \times  \dfrac{7}{22}

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 \dashrightarrow \: \sf{}r =\cancel{198} \times  \dfrac{1}{ \cancel2}  \times  \dfrac{7}{22}

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 \dashrightarrow \: \sf{}r =99 \times  \dfrac{1}{ 1}  \times  \dfrac{7}{22}

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 \dashrightarrow \: \sf{}r =99 \times \dfrac{7}{22}

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 \dashrightarrow \: \sf{}r =11 \times 3 \times 3 \times \dfrac{7}{2 \times 11}

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 \dashrightarrow \: \sf{}r =\cancel{11} \times 3 \times 3 \times \dfrac{7}{2 \times \cancel{11} }

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 \dashrightarrow \: \sf{}r =3 \times 3 \times \dfrac{7}{2}

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 \dashrightarrow \: \sf{}r =\dfrac{3 \times 3 \times 7}{2}

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 \dashrightarrow \: \sf{}r =\dfrac{63}{2}

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 \dashrightarrow \: \sf{}r = 31.5

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Now Let's find diameter

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we know:

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 \hookrightarrow \rm{}Diameter = 2 \times radius

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 \hookrightarrow \sf{}Diameter = 2 \times 31.5

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 \hookrightarrow  \blue{ \underline{\boxed{ \sf{}Diameter =63}}}

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Finally Let's find Area of Circle:

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we know:

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 \bigstar \boxed{ \rm{}Area \: of \: circle =\pi {r}^{2} }

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 \dashrightarrow\sf{}Area \: of \: circle =\pi {r}^{2}

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 \dashrightarrow\sf{}Area \: of \: circle = \dfrac{22}{7} \times  {r}^{2}

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 \dashrightarrow\sf{}Area \: of \: circle = \dfrac{22}{7} \times  {31.5}^{2}

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 \dashrightarrow\sf{}Area \: of \: circle = \dfrac{22}{7} \times31.5 \times 31.5 \\

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 \dashrightarrow\sf{}Area \: of \: circle = \dfrac{21829.5}{7} \\

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 \dashrightarrow \underline{ \boxed{\sf{}Area \: of \: circle = 3118.5}} \\

\underline {\blue{~~~~~~~~~~~~~~~~~~~~~~~\:\:\:\:\bigstar~~~~~~~~~~~~~~~~~~~~~~~\:\:\:\:}}

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