Question

Find the diameter of a wire if the length is 1.0 m, resistance is 23 ohm, and resistivity is 1.84×10^(-6) ohm m.

CBSE
Class X​

Answer 1

Explanation:

π*r^2 = 1.84*10^-6*1/(23) =0.08*10-6

r^2 = 0.0254 *10^-6 = 0.159*10-3 mm

taking square root

r = 0.159*10-3 m = 0.159 mm

diameter =2*0.159 = 0.318 mm

Answer 2

Answer:

d= 2.5×10^-6m

Explanation:

d=?

l= 1m

R= 23ohm

rho = 1.84×10^-6

d = rho.length/(R×pi)

d = 1.86×10^-6×1/(22/7×23)

2.54×10^-6