Math, asked by anam706, 29 days ago


Find the diameter of circles having the
following areas.
5
1
(i) 5544 m2 (ii) 86-cm2 (iii) 346-cm?
8
2.
(iv) 616 m2 (v) 1386 m2
1620​

Answers

Answered by janhavigharat286
0

Answer:

1) Diameter = 42 m

2) Diameter = 5.25 cm

3) Diameter = 46.93 cm

Step-by-step explanation:

To find : The diameter of circles having the following areas ?

Solution :

The diameter of the circle is d=2rd=2r

The area of the circle is A=\pi r^2A=πr

2

1) A_1=5544\ m^2A

1

=5544 m

2

5544=\frac{22}{7}\times (r_1)^25544=

7

22

×(r

1

)

2

(r_1)^2=\frac{5544\times 7}{22}(r

1

)

2

=

22

5544×7

r_1=\sqrt{1764}r

1

=

1764

r_1=42\ mr

1

=42 m

The diameter is d_1=2\times 42=84\ cmd

1

=2×42=84 cm

2) A_2=86\frac{5}{8}=\frac{693}{8}\ cm^2A

2

=86

8

5

=

8

693

cm

2

\frac{693}{8}=\frac{22}{7}\times (r_2)^2

8

693

=

7

22

×(r

2

)

2

(r_2)^2=\frac{693\times 7}{22\times 8}(r

2

)

2

=

22×8

693×7

r_2=\sqrt{27.5625}r

2

=

27.5625

r_2=5.25\ cmr

2

=5.25 cm

The diameter is d_2=2\times 5.25=10.5\ cmd

2

=2×5.25=10.5 cm

3) A_3=\frac{3461}{2}\ cm^2A

3

=

2

3461

cm

2

\frac{3461}{2}=\frac{22}{7}\times (r_3)^2

2

3461

=

7

22

×(r

3

)

2

(r_3)^2=\frac{3461\times 7}{22\times 2}(r

3

)

2

=

22×2

3461×7

r_3=\sqrt{550.6136}r

3

=

550.6136

r_3=23.46\ cmr

3

=23.46 cm

The diameter is d_3=2\times 23.46=46.93\ cmd

3

=2×23.46=46.93 cm

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