Question

find the diameter of te circle whose centre is at (2, 0) and which passes through the point (7, -12)

Answer 1

Center = (2,0)

Point = (7, -12)

Formula =

$\sqrt{((x_{2}-x_{1} } )^2+ (y_{2}-y_{1} } )^2)}$

Distance of point from center  =

$\sqrt{(7-2)^{2} + (-12 - 0^2)} \\ \sqrt{5^2 + (-12)^2} \\ \sqrt{25+144}\\ \sqrt{169} \\ 13$

13 units  = radius

diameter = 2 * radius = 26 units