Find the diameter of the circle whose area is equal to the sum of the areas of the two circles of diameters 20 cm and 48 cm.
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to find diameter of circle [ d1 ]
given diameter of 2nd circle= 20cm
radius [ r₂] = 10 cm
diameter of 2rd circle = 48 cm
radius [r₃] = 24 cm
ATQ
πr₁² =πr₂² + πr₃²
лr₁² = л(r₂² + r₃²)
лr₁²/л = (10)² +(24)²
r₁² = 100 + 576
r₁² = 676
r₁= √676
r₁ = 26 cm
diameter= 2r₁ = 2*26 = 52 cm
given diameter of 2nd circle= 20cm
radius [ r₂] = 10 cm
diameter of 2rd circle = 48 cm
radius [r₃] = 24 cm
ATQ
πr₁² =πr₂² + πr₃²
лr₁² = л(r₂² + r₃²)
лr₁²/л = (10)² +(24)²
r₁² = 100 + 576
r₁² = 676
r₁= √676
r₁ = 26 cm
diameter= 2r₁ = 2*26 = 52 cm
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