Question

find the diff btw perimeter of sq and circle in the fig. given above​

Answer 1

Answer:

Step-by-step explanation:

Solⁿ

given,

r = 91 cm

We know that,

Area of circle = $\pi r^{2}$

So,

$(\frac{22}{7}) 91^{2}$

=>  $(\frac{22}{7}) 8281$

=> 22 x 1183  

=>  26026

again,

Area of square = $L^{2}$

So,

 $91^{2}$

=> 8281

the diff btw perimeter of sq and circle

26026 - 8281

= 17745

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