Question

Find the difference (5x^2 + 2x + 11) - (7 + 4x - 2x^2)

Answer 1

Answer:

7x² - 2x + 4

Step-by-step explanation:

To find the difference, simply subtract one sum from other.

(5x² + 2x + 11) - (7 + 4x - 2x²)

Remove the parenthesis ;

⇒ 5x² + 2x + 11 - 7 - 4x + 2x²

Take out the like terms aside;

⇒ 5x² + 2x² + 2x - 4x + 11 - 7

⇒ 7x² - 2x + 4

Hence, the answer is (7x² - 2x + 4).

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$\large{\underline{\underline{\mathfrak{\heartsuit \: Extra \: Information: \: \heartsuit}}}}$

While solving this type of questions, parenthesis must be taken properly. The negative sign before parenthesis changes the sign of other numbers in the bracket.

Answer 2

Solution

$( {5x}^{2} + 2x + 11) - (7 + 4x - {2x}^{2} )$

remove the bracket

$= > {5x}^{2} + 2x + 11 - 7 - 4x + {2x}^{2}$

Arrange the terms

$= > 5 {x}^{2} + 2 {x}^{2} + 2x - 4x + 11 - 7$

$= > 7 {x}^{2} - 2x + 4$

Verification

Let LHS = RHS

$(7 + 4x - 2 {x}^{2} ) + (7 {x}^{2} - 2x + 4) \: = 5 {x}^{2} + 2x + 11$

Remove the bracket

$= > 7 + 4x - 2 {x}^{2} + 7 {x}^{2} - 2x + 4$

Arrange the terms

$= > 7 + 4 + 4x - 2x - 2 {x}^{2} + 7 {x}^{2}$

$= > 11 + 2x + 5 {x}^{2}$

$= > 5 {x}^{2} + 2x + 11 \: = 5 {x}^{2} + 2x + 11$

HENCE, verified

Therefore the answer is

$7 {x}^{2} - 2x + 4$