Question

find the difference between(2, 3) , (4, 1) pair of points . the distance

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Answer 1

Answer:

$2 \sqrt{2}$

Step-by-step explanation:

P = (x1 , y1) = (2 , 3)

Q = (x2 , y2) = (4, 1)

By disatance Formula,

l(PQ) = $\sqrt{(x_{2} ^{2}-x_{1} ^{2})+(y_{2} ^{2}-y_{1} ^{2}) }$

l(PQ) = $\sqrt{(4-2)^2+(1-3)^2}$

l(PQ) = $\sqrt{2^2 + -2^2}$

l(PQ) = $\sqrt{4+4}$

l(PQ) = $2 \sqrt{2}$