find the difference between (3,2) and (11,8) in Co ordinate geometry
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Heya
______________________________
Difference between two points in co-ordinate geometry mean distance between two given points.
P1 = ( x1 , y1 )
And
p2 = ( x2 , y2 )
Then their Difference/Distance is given by
d = √{(x2 - x1)² + ( y2 - y1)² }
Here x1 = 3 , y1 = 2 , x2 = 11 and y2 = 8
=>
d = √{11 -3 )² + ( 8 - 2)²}
=>
d = √{64 + 36 }
=>
d = √(10)²
=>
d = 10
OR
d = -10
d = -10 will be rejected becoz distance can't be -ive
So, Difference/Distance between two given points is 10units
______________________________
Difference between two points in co-ordinate geometry mean distance between two given points.
P1 = ( x1 , y1 )
And
p2 = ( x2 , y2 )
Then their Difference/Distance is given by
d = √{(x2 - x1)² + ( y2 - y1)² }
Here x1 = 3 , y1 = 2 , x2 = 11 and y2 = 8
=>
d = √{11 -3 )² + ( 8 - 2)²}
=>
d = √{64 + 36 }
=>
d = √(10)²
=>
d = 10
OR
d = -10
d = -10 will be rejected becoz distance can't be -ive
So, Difference/Distance between two given points is 10units
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