find the difference between compound and simple interest on a sum of ₹12000 at therate of 12% p.a. for 2 years ( compounded annually )
Answers
Answered by
100
Principal- Rs.12000
Rate-12%
time-2 years
1.) amount- princiapal(1+rate/100)^t
A= 12000(1+12/100)^2
A= 12000(112/100)^2
A= 12000(28/25)^2
A= 12000*784/625
A= Rs.15052.8
CI- 15052.8-12000 = Rs.3052.8
2.) Simple interest= principal*rate*time/100
SI= 12000*12*2/100
SI= Rs.2880
3.) Difference-) CI-SI
= 3052.8-2880
=Rs.172.8
Rate-12%
time-2 years
1.) amount- princiapal(1+rate/100)^t
A= 12000(1+12/100)^2
A= 12000(112/100)^2
A= 12000(28/25)^2
A= 12000*784/625
A= Rs.15052.8
CI- 15052.8-12000 = Rs.3052.8
2.) Simple interest= principal*rate*time/100
SI= 12000*12*2/100
SI= Rs.2880
3.) Difference-) CI-SI
= 3052.8-2880
=Rs.172.8
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Answered by
38
P = 12000
R=12%
T= 2 years.
SI= 12000×12×2/100
= 2880
Now,
P=12000
R=12%
T=2 years.
CI = 12000[(1+12/100)^2-1]
= 12000 × 159/625
= 3052.8
A/Q
Ci - si
3052.8 - 2880
172.8. Ans
R=12%
T= 2 years.
SI= 12000×12×2/100
= 2880
Now,
P=12000
R=12%
T=2 years.
CI = 12000[(1+12/100)^2-1]
= 12000 × 159/625
= 3052.8
A/Q
Ci - si
3052.8 - 2880
172.8. Ans
sorry this is wrong answer
the ans is 172.80
Ya i have corrected it
Now it is right
Please mark it as brainlist
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