Find the difference between compound interest and simple interest on Rs 25000 for 2 years at 8% p.a. compound annually.
Answers
Answered by
2
Answer:
rs 4
Step-by-step explanation:
Given P=Rs.2,500,r=4%, N=2
CI=P(1+
100
R
)
2
−P=2,500(1+
100
4
)
2
−2,500=2,500(
100
2
104
2
−1)=
10,000
2,500×816
=Rs.204
SI=
100
P×T×R
=
100
2,500×4×2
=Rs.200
Difference=Rs.4
Answered by
6
Answer:
rs 160
Step-by-step explanation:
SI =( p×R×T)/100
SI = (25000×8%×2)/100
SI = 500×8 =4000
SI = 4000
A=p (1+r%/100)^2
A=25000 (1+8%/100)^2
A = 25000 (108/100)^2
A=25000×108/100×108/100
A = 5×54×108
A=29160
CI=A-P
CI =29160-25000=4160
CI = 4160
CI - SI
4160-4000 = 160
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