find the difference between compound interest and simple interest on rs 12000 and in 1and 1/2 years at 10% p.a compounded yearly.
Answers
Answered by
55
P = 12000. R = 10. T = 1AND 1/2 = 3/2
S. I. = P x R x T / 100
= 12000 * 10 * 3/100*2
= 120*5*3
=Rs. 1800
C. I. = P ( 1 + R/100) ^N * ( 1 + X/Y*R / 100 )
= 12000(1 + 10/100) ^ 1 * ( 1+ 1/2*10/100)
=12000(1 + 1/ 10 ) ^ 1 * (1 + 1*5 / 100 )
= 12000 ( 11/10) * (1 + 5/100)
= 12000 * 11/10 * 105 /100
= 12 * 11 * 105
= 13860 rs.
difference between C. I. and S. I.
= 13860 - 1800
= 12060 rs. Ans.
S. I. = P x R x T / 100
= 12000 * 10 * 3/100*2
= 120*5*3
=Rs. 1800
C. I. = P ( 1 + R/100) ^N * ( 1 + X/Y*R / 100 )
= 12000(1 + 10/100) ^ 1 * ( 1+ 1/2*10/100)
=12000(1 + 1/ 10 ) ^ 1 * (1 + 1*5 / 100 )
= 12000 ( 11/10) * (1 + 5/100)
= 12000 * 11/10 * 105 /100
= 12 * 11 * 105
= 13860 rs.
difference between C. I. and S. I.
= 13860 - 1800
= 12060 rs. Ans.
kashish190:
but if it is then I m srry there must be any calculations mistake otherwise the process is correct
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what oh
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nothing
I didnt understood
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Answered by
5
Answer:
12060 rs
Step-by-step explanation:
P = 12000, R = 10, T = 1 & 1/2 = 3/2
S.I = (P × R × T) /100
=12000×10×3/100×2
=120×5×2
=Rs. 1800
C.I = P(1+R/100)^N*(1+X/Y*R/100)
= 12000 (1+10/100)^1*(1+1/2*10/100)
=12000(11/100)^1*(1+1*5/100)
=12000(11/100)*(1+5/100)
=12000*11/100*105/100
=12*11*105
=13860 rs.
difference between C.I and S.I
= 13860-1800
= 12060 rs.
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