find the difference between compound interest and simple interest if principal is rupees 4000 and rate is 5% and number of years is two years
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For ,
N=2years
R=10 %
P=Rs4,000
We have S.I.= 100
PPN = 100
4,000×2×10 =Rs800
And on interest being compounded for 2 years and R=10 %,
Amount=P(1+100 R )
N=4,000×(1+ 100 10 )
2=4,000×1.1×1.1=Rs.4,840
So, C.I.=A−P=4,840−4,000=840
And required difference C.I.−S.I.=840−800=Rs40
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