find the difference between compound interest and simple interest on Rs.80, 000 for 1 yr at 15/2%, if the is compounded semi annually
Answers
Step-by-step explanation:
To calculate Si :
P = Rs 80,000
T = 1 year
R = 15/2 % p.a.
\begin{gathered}∴ \: Si\: = \: (\frac{PTR}{100 }) \\ \\ = Rs \: (\frac{80000 \times 1 \times 15}{100 \times 2} ) \\ \\ = Rs \: 6000\end{gathered}∴Si=(100PTR)=Rs(100×280000×1×15)=Rs6000
To calculate Ci :
P = Rs 8000
R = 15/2 % p.a. = 15/4 % per half year
Time = Rs 1 year = 2 half year
\begin{gathered}A = P \: ( 1 + \frac{R}{100} ) ^{n} \\ \\ = \: Rs \: 80000 \:( 1 + \frac{15}{400} ) ^{2} \\ \\ = Rs \: 80000 \: ( \frac{83}{80} )^{2} \\ \\ = Rs \: 80000 \times \frac{83}{80} \times \frac{83}{80} \\ \\ = Rs \: 86112.50\end{gathered}A=P(1+100R)n=Rs80000(1+40015)2=Rs80000(8083)2=Rs80000×8083×8083=Rs86112.50
∴ Ci = Rs ( 86,112.50 - 80000)
= Rs 6,112.50
∴ Ci - Si = Rs ( 6,112.50-6,000 )
= Rs 112.50
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)=Rs.320
)=Rs.320∴(C.I.)−(S.I.)=Rs.(344.81−320)=Rs.24.81
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