Find the difference between S. and C.I on Rs. 2000 for 3/2 years at 6% p.a compound interest
being reckoned half yearly,
Answers
Step-by-step explanation:
Given : P = Rs. 16000, R = 5 %, T = 3/2 years
Simple Interest = (P*R*T)/100
= (16000*5*3)/(2*100)
Simple Interest = Rs. 1200
Case 2
Compound Interest
Given : P = Rs. 16000, R = 5 % per annum and compounded half yearly so, rate of interest = 2.5 %
T = 3/2 years = 1 year and one half year = 3 half years
A = P (1 +r/100)ⁿ
= 16000 (1 + 2.5/100)³
= 16000 × 102.5/100 × 102.5/100 × 102.5/100
A = Rs. 17230.25
So, compound interest = 17230.25 - 16000 = Rs. 1230.25
Difference between compound interest and simple interest = 1230.25 - 1200 = Rs 30.25
Answer:
5.454 Be assured this is the right answer
Step-by-step explanation:
SI = P.R.T/ 100
or 2000 x 3 x 6/ 2 x 100
or 180
CI = A - P
CI = {2000 x (1 + 6/200)^2 x 3/2} - 2000
CI = 185.454
Therefore the difference is 5.454