Question

Find the difference between SI and CI on 15,625 at 12% per annum for 3 years​

Answer 1

Answer:

Step-by-step explanation:

SI=PTR/100

=15625*3*12/100

=562500/100

=5625

CI=P[(1+R/100)^T-1]

=15625[1+12/10)^3-1]

=15625[(1+0.12)^3-1]

=15625[(1.12)^3-1]

=15625[1.404928-1]

=15625*0.404928

-RS 6327

Difference between SI and CI =Rs 6327- Rs 5625

=Rs 702

Answer 2

Solution:-

At SI:

Principal (P) $\sf{{= 15,625}}$

Rate (R) $\sf{{= 12 \% p.a.}}$

Time (T) $\sf{{= 3 \ years}}$

Simple Interest $\sf\dfrac{= P\times R\times T}{100}$

$= \sf\dfrac{15625\times 12\times 3}{100}$

$\sf{{= 5,625}}$

At CI:

For I year :-

P $\sf{{= 15,625}}$

R $\sf{{= 12 \% p.a.}}$

T $\sf{{= 1 \ year}}$

I $= \sf\dfrac{15625\times 12\times 1}{100}$

$\sf{{= 1875}}$

Amount (A) $\sf{{=}}$ P + I

$\sf{{= 15,625 + 1,875}}$

$\sf{{= 17,500}}$

For II year :-

P $\sf{{= 17,500}}$

R $\sf{{= 12\% p.a.}}$

T $\sf{{= 1 \ year}}$

I $= \sf\dfrac{17,500\times 12\times 1}{100}$

$\sf{{= 2,100}}$

A $\sf{{= 17,500 + 2,100}}$

$\sf{{= 19,600}}$

For III year :-

P $\sf{{= 19,600}}$

R $\sf{{= 12\% p.a.}}$

T $\sf{{= 1 \ year}}$

I $= \sf\dfrac{19,600\times 12\times 1}{100}$$= \sf{{2,352}}$

A $\sf{{= 19,600 + 2,352}}$

$\sf{{= 21,952}}$

C.I. $\sf{{= 21,952 - 15,625}}$

$\sf{{= 6,327}}$

∴ C.I. - S.I. $\sf{{= 6,327 - 5,625}}$

$\sf{{= 702}}$

$\LARGE \boxed{\sf{{C.I. - S.I. = 702}}}$