Question

find the difference between simple intetest and compound interest on rs 14400 for 2 years the interest being compounded at 10 percent​

Answer 1

Answer:

CI - SI = 144

Step-by-step explanation:

Formula = difference ( CI - SI)

= principal*(rate of interest/100)^2. [for 2 year]

= 14400 * (10/100)^2

= 14400 * 1/100

=144

Answer 2

AnswEr :

$\bold{Given} \begin{cases} \sf{Principal=Rs. 14400} \\ \sf{Rate=10\% \: p.a.} \\ \sf{Time=2 \: Yr.}\\ \sf{Find \: Diff. \: of \: CI \: and \: SI}\end{cases}$

$\leadsto\sf{Difference = Compound \: Interest - Simple \: Interest}$

$\leadsto\sf{Diff. = \bigg[P \bigg(1 + \dfrac{r}{100} \bigg)^{t} - 1 \bigg]- \bigg[\dfrac{PRT}{100} }\bigg]$

$\leadsto\sf{Diff. = \bigg[14400 \bigg(1 + \cancel\dfrac{10}{100} \bigg)^{2} - 1 \bigg]- \bigg[\dfrac{144 \cancel{00} \times 10 \times 2} {\cancel{100}} } \bigg]$

$\leadsto\sf{Diff. = \bigg[14400 \bigg(1 + \dfrac{1}{10} \bigg)^{2} - 1 \bigg]- \bigg[144 \times 10 \times 2 } \bigg]$

$\leadsto\sf{Diff. = \bigg[14400 \bigg( \dfrac{11}{10} \bigg)^{2} - 1 \bigg]- 2880 }$

$\leadsto\sf{Diff. = \bigg[14400 \bigg( \dfrac{121}{100} - 1\bigg) \bigg]- 2880}$

$\leadsto\sf{Diff. = \bigg(144 \cancel{00} \times \dfrac{21}{ \cancel{100}} \bigg) - 2880}$

$\leadsto\sf{Diff. = (144 \times 21) - 2880}$

$\leadsto\sf{Diff.= Rs. (3024 - 2880)}$

$\leadsto \large \boxed{\sf{Diff. = Rs. \: 144}}$

⠀

჻ Difference of CI and SI is Rs. 144