Question

find the difference between smiple interest and compound interest on ₹ 4000 at 10% for 2 years​

Answer 1

Answer:

simple interest= p×r×t/100

4000×10×2 /100= 800

amount= 4000(1+10/100)×10

4000×110/100×110/100

=4840

ci= a-p

4840-4000

840

difference= 40

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Answer 2

Step-by-step explanation:

Question:-

Find the difference between simple interest and compound interest on ₹4000 at 10% for 2 years.

Answer:-

Given :-

• The principal is ₹4000.

• The rate is 10% per annum.

• The time is 2 years.

To find :-

The difference between simple interest and compound sentence of the above amount.

Process :-

Simple Interest :-

P = ₹4000

R = 10%

T = 2 years

For 1st year:-

$∴ SI = \frac{P \times R \times T}{100} \\ \\ ⇒SI = \frac{4000×10×1}{100} \\ \\ ⇒SI = ₹400 \\ \\ ∴Total \: money \: = ₹(4000+400) \\ = ₹4400$

For 2nd year:-

$⇒SI = \frac{P×R× T}{100} \\ \\ ⇒SI = \frac{4000×10×1}{100} \\ \\ ⇒SI = ₹400 \\ \\ ∴ Total \: amount = ₹ (4400 + 400) \\ = ₹4800$

Simple Interest = ₹4800

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Compound Interest :-

P = ₹4000

R = 10%

T = 2 years

$∴Amount = P (1+ \frac{r}{100} {)}^{n} \\ \\ ⇒Amount = 4000(1+ \frac{10}{100} {)}^{2} \\ \\ ⇒Amount = 4000 ( \frac{110}{100} {)}^{2} \\ \\ ⇒Amount = 4000 × \frac{110}{100} × \frac{110}{100} \\ \\ ⇒Amount = ₹4840$

Compound interest = ₹4840

Difference between simple interest and compound interest :-

= ₹ ( 4840 - 4800 )

= ₹ 40

∴ The difference between the simple interest and compound interest of the above amount is ₹ 40.

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