Math, asked by sanyukta2939, 1 month ago

Find the difference between the area swept out by the minute hand of a clock which is 3.6 centimeters long and the hour hand which is 2.9 centimeters long.

Answers

Answered by mahipc08
0

Answer:

65.94cm 2

Step-by-step explanation:

Time = 11:20 am to 11:55am = 35 minutes

60 minutes = 360°

So, 1 minute = \frac{360}{60}

60

360

So, 1 minute =6°

So, 35 minutes = 6 \times 35=210^{\circ}6×35=210

The hour hand of a clock is 6cm long .

Area swept by hour hand = \frac{\theta}{360} \pi r^2

360

θ

πr

2

= \frac{210}{360} 3.14 \times 6^2

360

210

3.14×6

2

= 65.9465.94

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