Question

Find the difference between the compound interest and simple interest on rs 1,20,000 for 3/2 years at the rate of 4% per annum.

Answer 1

Step-by-step explanation:

S.I = Pnr/100

C.I = P[(1+r/100)^a(1+b/c×r/100) - 1]

Given, P = 1,20,000 , r = 4% , n = 3/2 = 1 1/2

S.I = (1,20,000×3/2×4)/100 = 7,200

C.I = 1,20,000[(1+4/100)^1(1+(3/2×4)/100) - 1]

= 1,20,000[(1.04)(1.06) - 1]

= 12,288

C.I - S.I = 12,288 - 7,200 = 5,088

Answer 2

Answer:

96

Step-by-step explanation:

This question is same as the question above