find the difference between the compound interest and simple interest on 8000 in 2 yrs and 5per cent per annum
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the answer is 20rs use formulas
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Heya ☺
C.I. = P{(1+R/100)^n - 1}
= 8,000{(1+5/100)^2 - 1}
= 8,000{(100+5/100)^2 - 1}
= 8,000{(105/100)^2 - 1}
= 8,000{(21/20)^2 - 1}
= 8,000{(441/400) - 1}
= 8,000{441-400/400}
= 8,000 × 41/400
= ₹820
S.I. = P×R×T/100
= 8,000×5×2/100
= ₹800
Difference = C.I. - S.I.
= ₹(820-800)
= ₹20
Thanks
C.I. = P{(1+R/100)^n - 1}
= 8,000{(1+5/100)^2 - 1}
= 8,000{(100+5/100)^2 - 1}
= 8,000{(105/100)^2 - 1}
= 8,000{(21/20)^2 - 1}
= 8,000{(441/400) - 1}
= 8,000{441-400/400}
= 8,000 × 41/400
= ₹820
S.I. = P×R×T/100
= 8,000×5×2/100
= ₹800
Difference = C.I. - S.I.
= ₹(820-800)
= ₹20
Thanks
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