find the difference between the compound interest and simple interest on a sum of 10000 at the rate of 10% p. a for 2 years (compounded annually)
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Answered by
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A=P(1+R/100)^T
A=10000 (1+10/100)^2
A=10000(11/10)^2
A=10000×11/10×11/10
A=12100
C.I=A-P
C. I=12100-10000
C. I=2100
S. I=P×R×T/100
S. I=10000×10×2/100
S. I=2000
Difference = C. I-S. I
= 2100-2000
=100
PLEASE FOLLOW ME AND MAKE ME BRAINLIEST
A=10000 (1+10/100)^2
A=10000(11/10)^2
A=10000×11/10×11/10
A=12100
C.I=A-P
C. I=12100-10000
C. I=2100
S. I=P×R×T/100
S. I=10000×10×2/100
S. I=2000
Difference = C. I-S. I
= 2100-2000
=100
PLEASE FOLLOW ME AND MAKE ME BRAINLIEST
sarthak1335:
I think it must be help yoo
Answered by
1
A=10000 (1+10/100)^2
A=10000(11/10)^2
A=10000×11/10×11/10
A=12100
C.I=A-P
C. I=12100-10000
C. I=2100
S. I=P×R×T/100
S. I=10000×10×2/100
S. I=2000
Difference = C. I-S. I
= 2100-2000
=100
PLEASE FOLLOW ME AND MAKE ME BRAINLIEST
:
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