Math, asked by poonamyadav5348, 7 months ago


Find the difference between the compound interest and the simple interest on
* 30,000 at 7% per annum for three years.​

Answers

Answered by mddilshad11ab
128

\sf\large\underline\blue{Given:}

\tt{\implies Principal=Rs.30000}

\tt{\implies Rate=7\%}

\tt{\implies Time=3\: years}

\sf\large\underline\blue{To\: Find:}

\tt{\implies Difference\:_{(CI-SI)}=?}

\sf\large\underline\blue{Solution:}

  • To calculate the difference between compound interest and simple interest , at first we have to find out both simple interest and compound interest separately then subract to eachother.]

\sf\small\underline\green{Calculation\:for\:SI:}

\sf\large\underline{Here,\:P=30000\:\:T=3\:\:R=7\%:}

\tt{\implies SI=\dfrac{P*T*R}{100}}

\tt{\implies SI=\dfrac{30000*3*7}{100}}

\tt{\implies SI=300*3*7}

\tt{\implies SI=Rs.6300}

\sf\small\underline\green{Calculation\:for\:CI:}

\sf\large\underline{Here,\:P=30000\:\:T=3\:\:R=7\%:}

\tt{\implies CI=P\bigg(1+\dfrac{r}{100}\bigg)^n-P}

\tt{\implies CI=30000\bigg(1+\dfrac{7}{100}\bigg)^3-30000}

\tt{\implies CI=30000\bigg(\dfrac{100+7}{100}\bigg)^3-30000}

\tt{\implies CI=30000\bigg(\dfrac{107}{100}\bigg)^3-30000}

\tt{\implies CI=30000*(1.07)^3-30000}

\tt{\implies CI=30000*1.225043-30000}

\tt{\implies CI=36,751.29-30000}

\tt{\implies CI=Rs.6,751.29}

\sf\large{Hence,}

\tt{\implies Difference\:_{(CI-SI)}=6751.29-6300}

\tt{\implies Difference\:_{(CI-SI)}=Rs.451.29}

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