Question

Find the difference between the compound interest and the simple interest on Rs 4000 for 2 years at 8% per annum.​

Answer 1

Question:

Find the difference between the compound interest and the simple interest on Rs 4000 for 2 years at 9% per annum.

To find:

• Difference between Compound interest and simple interest.

Given:

• P = Rs 4000
• R= 8%
• T= 2years

Solution:

Part 1:

To find Simple interest:

We know:

$\checkmark\boxed{ \rm{Simple \: interest = \frac{P \times R\times T}{100} }}$

By using this formula we can find value of Simple interest

$: \implies \sf{Simple \: interest = \dfrac{p \times r \times t}{100} }$

$: \implies \sf{Simple \: interest = \dfrac{4000 \times 2\times 8}{100} }$

$: \implies \sf{Simple \: interest = \dfrac{40 \: \cancel{00}\times 2\times 8}{\cancel{100}}}$

$: \implies \sf{Simple \: interest = 40 \times 2 \times 8}$

$: \implies \sf{Simple \: interest = 40 \times 16}$

$: \implies\underline {\boxed{\sf{Simple \: interest =Rs \: 640}}}$

Part 2:

To find Compound interest:

so to compound interest we should know no value of amount , .°. first let's find Amount

1 year:

here:

• p= Rs 4000
• R=8%
• T=1 year

$: \implies \sf{Simple \: interest \: for \: 1 \: year = \dfrac{P \times R\times T}{100}}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = \dfrac{4000\times 8\times 1}{100}}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = \dfrac{40 \cancel{00}\times 8\times 1}{\cancel{100}}}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = 40 \times 8}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = Rs \: 320}$

Now Let's find Amount of 1 year:

$: \implies \sf{Amount \: of \: 1 \: year =P + simple \: interest}$

$: \implies \sf{Amount \: of \: 1 \: year =320+ 4000}$

$: \implies \sf{Amount \: of \: 1 \: year =Rs \: 40320}$

2 year:

here:

• P= Rs 40320
• R = 8%
• T=1 year

$: \implies \sf{Simple \: interest \: for \: 2 \: year = \dfrac{P \times R\times T}{100}}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = \dfrac{4320\times 8\times 1}{100}}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = \dfrac{432 \cancel{0}\times 8\times 1}{10\cancel{0}}}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = \dfrac{432\times 8\times 1}{10}}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = \dfrac{3456}{10}}$

$: \implies \sf{Simple \: interest \: for \: 1 \: year = \: Rs \: 345.6}$

Now Let's find Amount of 2 year:

$: \implies \sf{Amount \: of \: 2\: year =Amount \: of \: 1\: year+ simple \: interest \: of \: 2 \: year}$

$: \implies \sf{Amount \: of \: 1 \: year =4320+ 345.6}$

$: \implies \sf{Amount \: of \: 1 \: year =Rs \: 4665.6}$

Let's find Compound Interest :

$: \implies \sf{Compound \: Interest = 4665.6 - 4000}$

$: \implies \underline{\boxed{\sf{Compound \: Interest = Rs \: 665.6}}}$

Finally Let's find difference between compound interest and simple interest

$: \implies\sf{}Compound \:interest-Simple\:Interest$

$: \implies\sf{}665.6 - 640$

$: \implies \pink{\underline{ \boxed{\sf{}Rs \: 25.6}}}\checkmark$

.°.Difference between Compound interest and simple interest = Rs 25.6

Answer 2

hi i saw that u have givin so many thanks in one question.. hows that posible??