Question

find the difference between the compound interest and the simple interest on rupees 120000 for 1½ years​

Answer 1

Answer:

Given : P = Rs 12,000; n = 121 years and r = 10%

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 year

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200For next 1/2 year

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200For next 1/2 yearP = Rs 13,200; n = 1/2 year and r = 10%

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200For next 1/2 yearP = Rs 13,200; n = 1/2 year and r = 10%C.I.=P(1+2×100r)2×n=13,200(1+2×10010)21×n

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200For next 1/2 yearP = Rs 13,200; n = 1/2 year and r = 10%C.I.=P(1+2×100r)2×n=13,200(1+2×10010)21×n=13,200(2021)1

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200For next 1/2 yearP = Rs 13,200; n = 1/2 year and r = 10%C.I.=P(1+2×100r)2×n=13,200(1+2×10010)21×n=13,200(2021)1= Rs 13,860

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200For next 1/2 yearP = Rs 13,200; n = 1/2 year and r = 10%C.I.=P(1+2×100r)2×n=13,200(1+2×10010)21×n=13,200(2021)1= Rs 13,860∴ C.I. = Rs 13,860 - Rs 12,000 = Rs 1,860

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200For next 1/2 yearP = Rs 13,200; n = 1/2 year and r = 10%C.I.=P(1+2×100r)2×n=13,200(1+2×10010)21×n=13,200(2021)1= Rs 13,860∴ C.I. = Rs 13,860 - Rs 12,000 = Rs 1,860∴ Difference between C.I. and S.I.

Given : P = Rs 12,000; n = 121 years and r = 10%S.I.=100P×R×T=10012,000×10×23=Rs1,800To calculate C.I. For 1 yearP = Rs 12,000; n = 1 years and r = 10%C.I.=P(1+100r)n=12,000(1+10010)1=Rs13,200For next 1/2 yearP = Rs 13,200; n = 1/2 year and r = 10%C.I.=P(1+2×100r)2×n=13,200(1+2×10010)21×n=13,200(2021)1= Rs 13,860∴ C.I. = Rs 13,860 - Rs 12,000 = Rs 1,860∴ Difference between C.I. and S.I.= Rs 1,860 - Rs 1,800 = Rs 60

Answer 2

Answer:

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