Math, asked by aanya6840, 10 hours ago

Find the difference between the interest obtained for Rs.1000
at 12% per annum for 3 years and that for Rs. 1500 at 8% per
annum for 1

.

Answers

Answered by vikkiain
0

Answer:

240

Step-by-step explanation:

P1 = 1000, R1 = 12% and T1 = 3 year, then

S.I1 = P1xR1xT1/100 = 1000x12x3/100 = 360

Again,

P2 = 1500, R2 = 8% and T2 = 1 year, then

S.I2 = 1500x8x1/100 = 120

Now,

S.I1 - S.I2 = 360 - 120 = 240.

Answered by MonoranjanDas
0

Answer:

Rs. 240

Step-by-step explanation:

In case one

principal ,p = Rs. 1000

rate of interest, r = 12%

time , t= 3

interest, I = ?

we know that

i =  \frac{p \times r \times t}{100}

 =  > i =  \frac{1000 \times 12 \times 3}{100}

 =  > i  = 360

So, the interest = Rs. 360

In second case

principal , p = Rs. 1500

rate of interest, r = 8%

time , t= 1

interest, I = ?

we know that

i =  \frac{p \times r \times t}{100}

 =  > i =  \frac{1500 \times 8 \times 1}{100}

so \: i = 120

So, interest = Rs. 120

Hence the difference between the obtained in the two cases =Rs.360-Rs.120

= Rs. 240

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