find the difference between the point (a,b) (-a,-b)
Answers
Answer:
find the difference between the point (a,b) (-a,-b)
in this problem we have to find distance not difference
Explanation:
Given:-
the points (a,b) (-a,-b)
To find:-
the difference between the point (a,b) (-a,-b)
Solution:-
Given points are (a,b) and (-a,-b)
Let they be
(x1,y1)=(a,b)=>x1=a;y1=b
(x2,y2)=(-a,-b)=x2=-a;y2=-b
Used formula:-
If (x1,y1) and (x2,y2) are two points then the distance between them is √{(x2-x1)²+(y2-y1)²}
=>√{(-a-a)²+(-b-b)²}
=>√{(-2a)²+(-2b)²}
=>√(4a²+4b²)
=>√4(a²+b²)
=>2√(a²+b²) units
Answer:-
The distance between the given two points is 2√(a²+b²) units
Difference :-
(a,b) is in 1st quadrant
(-a,-b) is in 3rd quadrant
Given:-
the points (a,b) (-a,-b)
To find:-
the difference between the point (a,b) (-a,-b)
Solution:-
Given points are (a,b) and (-a,-b)
Let they be
(x1,y1)=(a,b)=>x1=a;y1=b
(x2,y2)=(-a,-b)=x2=-a;y2=-b
Used formula:-
If (x1,y1) and (x2,y2) are two points then the distance between them is √{(x2-x1)²+(y2-y1)²}
=>√{(-a-a)²+(-b-b)²}
=>√{(-2a)²+(-2b)²}
=>√(4a²+4b²)
=>√4(a²+b²)
=>2√(a²+b²) units
Answer:-
The distance between the given two points is 2√(a²+b²) units
Difference :-
(a,b) is in 1st quadrant
(-a,-b) is in 3rd quadrant