Question

find the difference between the simple interest and compound interest on rupees 10000 4 to years at the 5% per annum​

Answer 1

Answer:

Principal sum = ₹1000,

Interest rate = 10%p.a. ,

Time= 4yrs.

Simple interest = P.R.T/100 = 1000×10×4/100 = 400. Compound interest= P{1+ R/100}™ - P =1000{1+10/1000}^4-1000 = 1464.1 - 1000 = 464.1

Thus difference in interests= 464.1 - 400 = ₹64.1

Answer 2

Answer:

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Rs. 25

A = $p \times (1 + \frac{r}{100} )$

A = $10000 \times(1+\frac{5}{100} )$

A = $10000 \times \frac{21}{20} \times \frac{21}{20}$

A = Rs. 11,025

C.I = 11,025 - 10,000

C.I = 1,025

S.I = $\frac{p \times r \times t}{1100$

S.I = $\frac{10000 \times 5 \times 2}{100}$

S.I = Rs. 1,000

Difference = 1,025 - 1,000

Difference = Rs. 25

REGARDS:- V DHIVYAALAKSHMI ✌️✌️