Question

Find the difference between the simple interest and compound interest on ₹ 20000 at 8 p.c.p.a.

Answer 1

$\textbf{SOLUTION :}$

Here, Principal ( P ) = RS. 20,000

Rate ( R ) = 8 p.c.p.a.

Duration ( N ) = 2 years

Simple Interest ( S - I )

$= \: \frac{P \times N \times R}{100} \: \\ \\ = \: \frac{20000 \times 2 \times 8}{100} \\ \\ = \: 200 \times 16 \\ \\ = \: \textbf{ RS.3200} \\ \\ \\ \\ a = p \: (1 + \frac{r}{100} {)}^{n} \\ \\ = \: 20000 \: (1 + \frac{8}{100} {)}^{2} \\ \\ = \: 20000 \times \frac{108}{100} \times \frac{108}{100} \\ \\ = \: 2 \times 108 \times 108 = \: \textbf{RS. \: 23328}. \\ \\ \\ compound \: interest \: (c.i) = a - p \\ \\ = \: 23328 - 20000 \\ \\ \textbf{RS. \: 3328}.$

Difference between the simple interest and compound interest

» C.I. - S.I

» 3328 - 3200

» $\textbf{ RS. 128}$.



Ans : The difference between the simple interest and compound interest is RS. 128.

Answer 2

Answer:

formula for calculating difference between ci and si for 2 years is

P * (R²/100²)

20000 × 64/10000

= RS. 128

PLEASE MARK IT AS BRAINLIEST

Step-by-step explanation: