Find the difference between the simple interest and the compound interest on rs 30000 for 4 years at a rate of 12% p.a compounded annually.step step explanation please
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3
Answer:
Ci= p{(1+r/100)^n-1}
30000{(1+12/100)^4-1}
30000{(100+12/100)^4-1}
30000{(112/100)^4-1}
30000{4,04,928/100000-1
Therefore ci = 6751.29
Si= pxrxt/100
30000x7x3/100
=6300
Therefore si =6300
There difference= 6751.29 - 6300=451.29 answer.
Answered by
1
Answer:
hope it helps.........,
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