Question

Find the difference between the simple interest
and the compound inte
rest on Rs 500 for
I years at 6% per annan.​

Answer 1

Answer:

hi there!!

Given details are,

Principal (p) = Rs 50000

Rate (r) = 10 % per annum

Time (t) = 2 years

By using the formula, A = P (1 + R/100) 

n = 50000 (1 + 10/100)2 = 50000 (110/100)2 = Rs 60500 CI = Rs 60500 – 50000 = Rs 10500

We know that SI = (PTR)/100 = (50000 × 10 × 2)/100 = Rs 10000

Difference amount between CI and SI = 10500 – 10000 = Rs 500

Step-by-step explanation:

hope it was helpful for you..please mark the answer as brainlist thank you

Answer 2

Answer:

Rs 40.5

Step-by-step explanation:

S.I=

100

P×R×T

S.I=

100

5000×9×2

S.I=Rs. 900

We know that

A=P(1+

100

R

)

n

A=5000(1+

100

9

)

2

A=Rs. 5940.5

C.I=A−P

C.I=5940.5−5000

C.I=Rs940.5

Difference

=C.I−S.I

=Rs940.5−Rs900

=Rs40.5

Hence,

the answer is 40.5