Find the difference between the simple interest and the compound interest on rs5000 for 2 years at 9% per annum.
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Soln:-
P=Rs5000. T=2 yrs. R=9℅ per annum
S.I=P×R×T/100
=5000×9×2/100
=900 rupees
C.I.=P(1+r/100)^t -P
=5000(1+9/100)^2 -5000
=5000(109/100×109/100) -5000
=5940.5 -5000
=Rs940.5
Difference =940.5-900
= Rs40.5
P=Rs5000. T=2 yrs. R=9℅ per annum
S.I=P×R×T/100
=5000×9×2/100
=900 rupees
C.I.=P(1+r/100)^t -P
=5000(1+9/100)^2 -5000
=5000(109/100×109/100) -5000
=5940.5 -5000
=Rs940.5
Difference =940.5-900
= Rs40.5
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