Question

Find the difference between the simple interest andthe compound intereston Rs. 6000 for 2 years at 8% p.a.

Can i get the answer as quick as possible

thanks in advance

Answer 1

$\Huge\boxed {r.s=38.4}$

$\Large{\textsf{\textbf{\underline{\underline{Given\::}}}}}$

• $p = rs.6000$
• $r = 8\%p.a.$
• $t = 2 \: years.$

$\Large{\textsf{\textbf{\underline{\underline{To.find\::}}}}}$

$●diffrence \: between \\ \: ci \: and \: si$

$\Large{\textsf{\textbf{\underline{\underline{formulas.used\::}}}}}$

• $si = \frac{prt}{100}$
• $A = p \: (1 + \frac{r}{100} )t$
• $c.i = a-p$

$\Large{\textsf{\textbf{\underline{\underline{solusion\::}}}}}$

${\bf{1.case\::}}$

$➣to \: find \: s.i.$

$➣we \: know, \:$

$➣s.i. = \frac{p \times r \times t}{100}$

$➣s.i. = \frac{6000 \times 8 \times 2}{100}$

$\small{\textsf{\textbf{\underline{\underline{ ➣s.i = 960\::}}}}}$

${\bf{2.case\::}}$

$➣to \: find \: ci,$

$➣we \: know, \:$

$➣A = p(1 + \frac{r}{100} )t$

$➣a = 6000(1 + \frac{8}{100} ) {}^{2}$

$➣a = 6000(100 + \frac{8}{100} ) {}^{2}$

$➣a = 6000( \frac{108}{100} ) {}^{2}$

$➣a = 6000 \times \frac{108}{100} \times \frac{108}{100}$

$\small{\textsf{\textbf{\underline{\underline{➣A = 6998.4\::}}}}}$

${\bf{3.case\::}}$

$➣to.find.c.i$

$➣we.know. c.i = A - p$

$➣c.i = 6998.4 - 6000$

$\small{\textsf{\textbf{\underline{\underline{➣c.i = 998.4\::}}}}}$

$\small{\textsf{\textbf{\underline{\underline{now.finding.the.diffrence.between.ci.and.si\::}}}}}$

$➣c.i = 998•4$

$➣s.i = 960$

$➣difference = r.s (998.4 - 960)$

$\Large{\textsf{\textbf{\underline{\underline{➣r.s = 38.4\::}}}}}$

$\Large{\textsf{\textbf{\underline{\underline{form.the.soluaion\::}}}}}$

$●p = principal \\ ●r = rate \: of \: interest \\ ●t = time \\ ●si = simple \: interest \\ ●ci = compound \: interest \\ ●a = amount$