Math, asked by b26315, 6 hours ago

find the difference between the simple interst and the compound interest on rupees 5000 for 2 years at 9 % per annum​

Answers

Answered by Emaxan
0

Answer:

40.5 Rupees

Step-by-step explanation:

We know,

S.I= P×R×T/100 = 5000×9×2/100  =900Rs.

=5000(1+  0.09) squared

 

A=Rs. 5940.5

C.I.=A−P=5940.5−5000

                           =940.5

Difference=C.I−S.I

=940.5−900

=40.5 Rs.

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