Find the difference between TSA and LSA of a cuboid whose dimensions are 10cm x 5 cm x 3cm
Answers
Diagram :
Given
↠ Dimensions of cuboid = 10 cm × 5 cm × 3 cm
To find
→ Difference b/w TSA and LSA of cuboid.
Solution
Formula to be used :
➻ TSA of cuboid = 2(lb + bh + hl)
➻ LSA of cuboid = 2(l + b) × h
Now at first to find TSA of cuboid :
➊ TSA of cuboid :
➔ TSA = 2(10 × 5 + 5 × 3 + 3 × 10)
➔ TSA = 2(50 + 15 + 30)
➔ TSA = 2 (95) cm²
➔ TSA = 190 cm²
∴ TSA of cuboid = 190 cm²
Now LSA of cuboid :
➋ LSA of cuboid :
➔ LSA = 2(10 + 5) × 3
➔ LSA = 2 × 15 × 3
➔ LSA = 90 cm²
∴ LSA of cuboid = 90 cm²
Now difference b/w TSA and LSA :
↠ Difference = TSA - LSA
↠ Difference = (190 - 90) cm²
↠ Difference = 100 cm²
Therefore, difference between TSA and LSA of cuboid = 100 cm²
Answer:
100 cm²
Step-by-step explanation:
Given that, length is 10cm, breadth is 5cm & height is 3 cm of cuboid.
Total surface area of cuboid = 2(lb + bh + hl)
Substitute the values,
Total surface area = 2(10 × 5 + 5 × 3 + 3 × 10)
= 2(50 + 15 + 30)
= 2(95)
= 190 cm² .................(1)
Lateral surface area of cuboid = 2h(l + b)
Substitute the values,
Lateral surface area = 2*3(10 + 5)
= 6(15)
= 90 cm² ...................(2)
Now,
Difference between total surface area and lateral surface is (1) - (2)
= (190 - 90) cm²
= 100 cm²
Hence, the difference between total surface area and lateral surface is 100 cm².