find the difference in area of two squares,one with the length of side 6m and the other with length of the diagnal 6m
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Answered by
8
⤵⤵⤵HEY BUDDY HERE IS YOUR ANSWER...
1 / FIRST SIDES =6 M
AREA =6 ×4 M
AREA =24 M^2
2/ DIAGONAL= 6 M
AREA = 1/2 × D ^2
AREA =1/2 ×6^2
AREA = 1/2 ×36
AREA =18 M^2
SO, DIFERENCE IS AREA IS 6 M^2.
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1 / FIRST SIDES =6 M
AREA =6 ×4 M
AREA =24 M^2
2/ DIAGONAL= 6 M
AREA = 1/2 × D ^2
AREA =1/2 ×6^2
AREA = 1/2 ×36
AREA =18 M^2
SO, DIFERENCE IS AREA IS 6 M^2.
✔✔✔✔✔✔✔✔✔
HOPE ITS HELP YOU
_________________
MARK ME AS BRAINLIEST
Answered by
4
Answer:18.02cm²
Step-by-step explanation:
length of side of square 1 = 6cm
so area = 36 cm²
length of diagonal of square 2 = 6 cm
halves of diagonal = 3cm
side of the square = √3²+3²
= √18
= 4.24
area = 17.98 cm
difference = 18.02 cm²(ans)
hope it helps you!!!
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