Question

Find the difference in C.I and S.I For P=Rs 50950,R=4% P.A n=2 years.​

Answer 1

Answer:

• Difference between CI and SI is ₹ 82.52

Step-by-step explanation:

Given that:

• Principal = ₹ 50950
• Rate = 4% per annum
• Time = 2 years

To Find:

• Difference between CI and SI.

Solution:

Finding Compound Interest:

As we know that:

$\sf{Amount=Principal\bigg(1+\dfrac{Rate}{100}\bigg)^{Time}}$

Substituting the values,

$\sf{Amount=50950\bigg(1+\dfrac{4}{100}\bigg)^{2}}$

Adding the numbers,

$\sf{\longmapsto50950\bigg(\dfrac{100+4}{100}\bigg)^{2}}$

$\sf{\longmapsto50950\bigg(\dfrac{104}{100}\bigg)^{2}}$

Reducing the numbers,

$\sf{\longmapsto50950\bigg(\dfrac{26}{25}\bigg)^{2}}$

Opening the brackets,

$\sf{\longmapsto50950\times\dfrac{26}{25}\times\dfrac{26}{25}}$

Multiplying the numbers,

$\longmapsto\sf{\dfrac{3,44,42,200}{625}}$

Dividing the numbers,

$\sf{\longmapsto55,107.52}$

Hence, amount = ₹ 55,107.52

Now,

As we know that,

• CI = Amount - Principal

Substituting the values,

CI = ₹(55,107.52 - 50950)

CI = ₹ 4,157.52

Hence, CI = ₹ 4,157.52

Finding Simple Interest:

As we know that:

$\sf SI=\dfrac{P\times R\times T}{100}$

Where,

• P = Principal
• R = Rate
• T = Time

Substituting the values,

$\sf SI=\dfrac{50950\times 4\times 2}{100}$

Cutting off the zeros,

$\sf \longmapsto\dfrac{5095\!\!\!\not{0}\times 4\times 2}{10\!\!\!\not{0}}$

$\sf \longmapsto\dfrac{5095\times 4\times 2}{10}$

Multiplying the numbers,

$\sf \longmapsto\dfrac{40760}{10}$

Dividing the numbers,

$\sf \longmapsto4076$

Hence, SI = ₹ 4076

Finding difference between CI and SI:

Difference = CI - SI

↪ ₹(4157.52 - 4076)

↪ ₹ 81.52

Hence, the difference between CI and SI is ₹ 82.52