Math, asked by shrdasingh3, 8 months ago

Find the difference in the place values of two 8s in the number 25,83,82,127

Answers

Answered by Anonymous
17

Step-by-step explanation:

Place value of first 8 in 25,83,82,127 = 80,00,000

Place value of second 8 in 25,83,82,127 = 80,000

Difference = 80,00,000 - 80,000

= 79,20,000

I hope it helps you .

Answered by smithasijotsl
6

Answer:

The difference in the place values of two 8s in the number 25,83,82,127 = 79,20,000

Step-by-step explanation:

Given number is 25,83,82,127

To find,

The difference in the place values of the two 8's in the numbers

Solution:

The place value of a digit is defined as the value of the position of the digit in the number.

The place value of a number in the Indian system is of the order Ones, Tens, Hundreds, Thousands, Ten thousands, Lakhs, Ten lakhs, Crores, Ten crores from right to left

Here, in the number 25,83,82,127 the first '8' when we go from right to left is in the ten thousands place

∴ The place value of the first 8 from the right = 8×10,000 = 80000

The second '8' when we go from right to left is in 'ten lakhs' place.

∴The place value of the second 8 from the right = 8×10,00,000  = 80,00,000

The difference between the place values = 80,00,000 - 80,000

=79,20,000

∴ The difference in the place values of two 8s in the number 25,83,82,127 = 79,20,000

#SPJ2

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