Question

find the difference of 10x-5(2-y)to gives 5 different values of x and y​

Answer 1

Step-by-step explanation:

Given:

find the difference of 10x-5(2-y)to gives 5 different values of x and y

To find: 5 different values of x and y

Solution:

Let

$10x - 5(2 - y) = 0 \\ \\ 10x - 10 + 5y = 0 \\ \\ 10x + 5y = 10 \\ \\ 2x + y = 2 \\ \\ y = 2 - 2x$

To find 5 Solutions

Case1: When x= 0

$y = 2 - 2 \times 0 \\ \\ y = 2$

A(0,2)

Case2:When x=1

$y = 2 - 2 \times 1 \\ \\ y = 2 - 2 \\ \\ y = 0$

B(1,0)

Case3: When x= -1

$y = 2 - 2 \times ( - 1) \\ \\ y = 2 + 2 \\ \\ y = 4$

C(-1,4)

Case4:When x= -2

$y = 2 - 2( - 2) \\ \\ y = 2 + 4 \\ \\ y = 6$

D(-2,6)

Case5:When x= 2

$y = 2 - 2(2) \\ \\ y = 2 - 4 \\ \\ y = - 2$

E(2,-2)

Thus,

Five Solutions are

(0,2)

(1,0)

(-1,4)

(-2,6)

(2,-2)

Hope it helps you.

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Answer 2

Answer:

Five Solutions are

Five Solutions are(0,2)

Five Solutions are(0,2)(1,0)

Five Solutions are(0,2)(1,0)(-1,4)

Five Solutions are(0,2)(1,0)(-1,4)(-2,6)

Five Solutions are(0,2)(1,0)(-1,4)(-2,6)(2,-2)