Find the difference of compound interest and simple interest on a sum of 4400 at 15% per annum for 2 years.
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Solution is in pic, C.I-S.I= Rs 99
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Solution is in pic, C.I-S.I= Rs 99
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Answered by
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Given sum(p) = Rs 4400, rate of interest(r) = 15%, time(t) = 2 years
S.I = p*t*r/100
= 4400*15*2/100
= Rs 1320
C.I = p*t*r/100
= 4400*15*1/100
= 660
Amount = 4400+660 = Rs 5060
Amount of 1 st year = sum of 2 nd year
C.I for 2 nd year = 5060*15*1/100
= Rs 759
C.I = 759+660 = Rs 1419
S.I = Rs 1320
C.I = Rs 1419
Difference between C.I and S.I = 1419 - 1320 = Rs 99
S.I = p*t*r/100
= 4400*15*2/100
= Rs 1320
C.I = p*t*r/100
= 4400*15*1/100
= 660
Amount = 4400+660 = Rs 5060
Amount of 1 st year = sum of 2 nd year
C.I for 2 nd year = 5060*15*1/100
= Rs 759
C.I = 759+660 = Rs 1419
S.I = Rs 1320
C.I = Rs 1419
Difference between C.I and S.I = 1419 - 1320 = Rs 99
Anonymous:
thanks
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