Question

find the difference of: (d) 2pq + rs - pr - 2qs from pq - 2rs + 2pr + qs (e) 5 - x - 4y + 4z from 5x – 7y + 2z > 2 give me step by step answer please​

Answer 1

Step-by-step explanation:

(deference means subtraction)

d) pq - 2rs + 2pr + qs - (2pq + rs - pr - 2qs)

pq - 2rs + 2pr + qs - 2pq - rs +pr +2qs

= - pq - 3rs + 3pr + 3qs

e) 5x – 7y + 2z - (5 - x - 4y + 4z)

5x – 7y + 2z - 5 +x + 4y - 4z

= 6x - 3y - 2z - 5