Question

find the difference of sum of 3x^2-4x+7 and 10x^2-8x+4 and the sum of x^2-7x+8 and 4x^2-3x- 9

Answer 1

(3x^2-4x+7+10x^2-8x+4)-(x^2-7x+8+4x^2-3x-9)
=> (13x^2-12x+11)-(5x^2-10x-1)
=> 13x^2-12x+11-5x^2+10x+1
=> 13x^2-5x^2-12x+10x+1+11
=> 7x^2 - 2x + 12

Answer 2

➡HERE IS YOUR ANSWER⬇

The sum of the first two terms is

$= (3 {x}^{2} - 4x + 7) + (10 {x}^{2} - 8x + 4) \\ \\ = (3 + 10) {x}^{2} + ( - 4 - 8)x + (7 + 4) \\ \\ = 13 {x}^{2} - 12x + 11$

and the sum of the last two terms is

$= ( {x}^{2} - 7x + 8) + (4 {x}^{2} - 3x - 9) \\ \\ = (1 + 4) {x}^{2} + ( - 7 - 3)x + (8 - 9) \\ \\ = 5 {x}^{2} - 10x - 1$

So, the difference of the sums

$= (13 {x}^{2} - 12x + 11) - (5 {x}^{2} - 10x - 1) \\ \\ = (13 - 5) {x}^{2} + ( - 12 + 10)x + (11 + 1) \\ \\ = 8 {x}^{2} - 2x + 12$

⬆HOPE THIS HELPS YOU⬅