Question

Find the difference of sum of successors and predecessor of the first five natural numbers.

Answer 1

Answer:

success is 35,predecess is 36

Answer 2

Answer:

The difference will be 10.

Step-by-step explanation:

Natural numbers are all positive integers.

i.e. 1, 2, 3, 4, 5...

(0 is nor positive neither negative)

Successors are one more.

i.e.

• 1 is the successor of 0.
• 2 is the successor of 1.
• 567 is the successor of 566.
• 0 is the successor of -1.

Predecessors are one less.

i.e.

• 0 is the predecessor of 1.
• -1 is the predecessor of 0.
• 3 is the predecessor of 4.

Now, the first five natural numbers are:

1, 2, 3, 4, 5

Successors of the first five natural numbers are:

2, 3, 4, 5, 6

Therefore the sum of the successors of the first five natural numbers will be:

$2 + 3 + 4 + 5 + 6 = 20$

Predecessors of the first five natural numbers are: 0, 1, 2, 3, 4

Therefore the sum of the predecessors of the first five natural numbers will be:

$0 + 1 + 2 + 3 + 4 = 10$

Hence,

The difference between the sum of the successors and predecessors of the first five natural numbers will be:

$= 20 - 10$

$= 10$