Question

Find the difference of the above sums

Answer 1

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Answer 2

a)
$10 \times \frac{2}{3} - 5 \times \frac{1}{6} \\ \\ \frac{32}{3} - \frac{31}{6} \\ \frac{64 - 31}{6} \\ \frac{33}{6} \\ \frac{11}{2}$
$\frac{9}{4} - \frac{1}{4} \\ \frac{9 - 1}{4} \\ \frac{8}{4} = 2$

$\frac{17}{16} - \frac{11}{24} \\ \frac{51 - 22}{48} \\ \frac{29}{48}$
$3 \frac{3}{4} - \frac{7}{10}$