Math, asked by kmunna8711, 7 months ago

Find the difference of the following quadratic equation: 6x2-(root2-root3)x-root2=0

Answers

Answered by tiwanasavitojs

1

Step-by-step explanation:

6x2-(root2-root3)x-root2 =0

6x2-root2x+root3x-root2=0

x(root3 x-root2)+1(root3x-root2)=0

(x+1)(root3x-root2)=0

x=-1 or x=root2/3

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