Question

find the differenciation of y=cosx.tanx
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Answer 1

Answer:

cos(x)

Explanation:

y=cos(x).sin(x)/cos(x)

then

y=cos(x).sin(x)/cos(x)

get cancelled

y=sin(x)

then dy/dx=d{sin(x)}/dx

=cos(x)

Answer 2

Answer:

Explanation:- y=cosx.tanx

So, differentiation of y or y' = differentiation of cosx × tanx + cosx × differentiation of tanx ( by product rule)

So, y'= -sinx.tanx + cosx.sec^2x