find the differentation of the question d/dx(sinx/1+tanx)
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Step-by-step explanation:
y = sinx/ 1 + tanx
dy/dx = [d(sinx)/dx * (1 + tanx) - sinx * d(1 + tanx)/dy]/(1 + tanx)^2 [BY QUOTEINT RULE]
dy/dx = [cosx(1 + tanx) - sinx(sec^2 x)]/(1 + tanx)^2
dy/dx =[cosx + sinx - tanx*secx]/(1 + tanx)^2
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Answer's in the pic bro.
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