Question

find the differential coefficient of e^xlogx(2x^2+3)​

Answer 1

Answer:

$\frac{d}{dx}( {e}^{x} log(x)(2 {x}^{2} + 3)) = >$

${e}^{x} ( 2{x}^{2} + 3) \frac{d}{dx}( log(x) ) +$

${e}^{x} log(x) \frac{d}{dx} (2 {x}^{2} + 3) +$

$log(x) (2 {x}^{2} + 3) \frac{d}{dx}( {e}^{x} ) = >$

${e}^{x}(2 {x}^{2} + 3)( \frac{1}{x} ) + {e}^{x} 4x log(x) +$

${e}^{x} log(x) ( 2{x}^{2} + 3)$

$= > {e}^{x} log(x) (2 {x}^{2} + 3 + 4x) +$

${e}^{x} (\frac{2 {x}^{2} + 3 }{x} )$

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