Question

Find the differential coefficient of sin 2.​

Answer 1

Explanation:

We have,

g(x)=sin 2x

Put x=x+h

g(x+h)=sin 2(x+h)

We know that

g

′

(x)=lim

h→ 0

h

g(x+h)−g(x)

Therefore,

g

′

(x)=lim

h→ 0

h

sin 2(x+h)−sin 2x

g

′

(x)=lim

h→ 0

h

2cos

2

2x+2h+2x

.sin

2

2x+2h−2x

g

′

(x)=lim

h→ 0

h

2cos (2x+h).sin h

g

′

(x)=2cos (2x+0).×1

g

′

(x)=2cos 2x

Answer 2

Explanation:

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